j^-2/j^-2=1

Solution for j^-2/j^-2=1 equation:

j^-2/j^-2=1

We move all terms to the left:

j^-2/j^-2-(1)=0


Domain of the equation: j^!=0

j!=0/1

j!=0

j∈R


We add all the numbers together, and all the variables

j-2/j^-3=0

We multiply all the terms by the denominator


j*j^-3*j^-2=0

We add all the numbers together, and all the variables

-3j+j*j^-2=0

Wy multiply elements

j^2-3j-2=0

a = 1; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·1·(-2)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{17}}{2*1}=\frac{3-\sqrt{17}}{2}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{17}}{2*1}=\frac{3+\sqrt{17}}{2}
$